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## mec vect

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Catégorie :Category: mViewer GX Creator Lua TI-Nspire
Auteur Author: alexisrael
Type : Classeur 3.6
Page(s) : 41
Taille Size: 2.49 Mo MB
Mis en ligne Uploaded: 14/02/2020 - 15:08:16
Visibilité Visibility: Archive publique

### Description

PROBLEM 2.1 PROBLEM 2.2

Two forces P and Q are applied as shown at Point A of a hook support. Knowing that Two forces P and Q are applied as shown at Point A of a hook support. Knowing that
P = 75 N and Q = 125 N, determine graphically the magnitude and direction of their P = 60 lb and Q = 25 lb, determine graphically the magnitude and direction of their
resultant using (a) the parallelogram law, (b) the triangle rule. resultant using (a) the parallelogram law, (b) the triangle rule.

SOLUTION SOLUTION
(a) Parallelogram law: (a) Parallelogram law:

(b) Triangle rule: (b) Triangle rule:

We measure: R = 77.1 lb, α = 85.4° R = 77.1 lb 85.4° !
We measure: R = 179 N, α = 75.1° R = 179 N 75.1° !

reproduced or distributed in any form or by any means, without the prior written permission of the publisher, or used beyond the limited reproduced or distributed in any form or by any means, without the prior written permission of the publisher, or used beyond the limited
distribution to teachers and educators permitted by McGraw-Hill for their individual course preparation. If you are a student using this Manual, distribution to teachers and educators permitted by McGraw-Hill for their individual course preparation. If you are a student using this Manual,
you are using it without permission. you are using it without permission.

3 4
PROBLEM 2.3 PROBLEM 2.4

The cable stays AB and AD help support pole AC. Knowing Two forces are applied at Point B of beam AB. Determine
that the tension is 120 lb in AB and 40 lb in AD, determine graphically the magnitude and direction of their resultant using
graphically the magnitude and direction of the resultant of the (a) the parallelogram law, (b) the triangle rule.
forces exerted by the stays at A using (a) the parallelogram
law, (b) the triangle rule.

SOLUTION
(a) Parallelogram law:
SOLUTION

(b) Triangle rule:

We measure: α = 51.3°
β = 59.0°
(a) Parallelogram law:

We measure: R = 3.30 kN, α = 66.6° R = 3.30 kN 66.6° !

(b) Triangle rule:

We measure: R = 139.1 lb, γ = 67.0° R = 139.1 lb 67.0° !

reproduced or distributed in any form or by any means, without the prior written permission of the publisher, or used beyond the limited reproduced or distributed in any form or by any means, without the prior written permission of the publisher, or used beyond the limited
distribution to teachers and educators permitted by McGraw-Hill for their individual course preparation. If you are a student using this Manual, distribution to teachers and educators permitted by McGraw-Hill for their individual course preparation. If you are a student using this Manual,
you are using it without permission. you are using it without permission.

5 6
PROBLEM 2.5 PROBLEM 2.6

The 300-lb force is to be resolved into components along lines a-a′ and b-b′. The 300-lb force is to be resolved into components along lines a-a′ and b-b′.
(a) Determine the angle α by trigonometry knowing that the component (a) Determine the angle α by trigonometry knowing that the component along
along line a-a′ is to be 240 lb. (b) What is the corresponding value of the line b-b′ is to be 120 lb. (b) What is the corresponding value of the component
component along b-b′? along a-a′?

SOLUTION SOLUTION
(a) Using the triangle rule and law of sines: Using the triangle rule and law of sines:
sin β sin 60° sin α sin 60°
= (a) =
240 lb 300 lb 120 lb 300 lb
sin β = 0.69282 sin α = 0.34641
β = 43.854° α = 20.268° α = 20.3°
α + β + 60° = 180°
α = 180° − 60° − 43.854° (b) α + β + 60° = 180°
= 76.146° α = 76.1° β =...

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59.92 Ko KB mec_vect/41.tns
645.48 Ko KB mec_vect/31-40.tns
654.32 Ko KB mec_vect/01-10.tns
620.85 Ko KB mec_vect/11-20.tns
653.38 Ko KB mec_vect/21-30.tns

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